In article ,
Bill Smythe wrote:
Can anybody come up with a vertically symmetric chess position in which,
with best play by both sides, the second player to move wins?

"Vertically symmetric" means that, for example, if there is a white knight
on f3, then there is a black knight on f6.

Bill Smythe

Yes.



White King g1, pawns f6,h6.

Black King h8, pawns f3,h3. (But you knew that already.)


Much harder puzzle: Same task but you're not allowed to use any pawns.

NDE

On 9 Jul 2003 02:18:00 GMT, Noam D. Elkies
wrote:

In article , I wrote:



White King g1, pawns f6,h6.

Black King h8, pawns f3,h3. (But you knew that already.)

That is, Black King on *g8*, of course...


That's a great solution. Very elegant.

I like the way if the white king just moves one to the left, the
pushing pawn creates a position where he can't move back to either of
the G squares.
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